Young Double slit experiment
Mathematical Approach of Youngs double slit experiment
Let two light source S1 and S2 are narrow parallel slit sepearated by a distance 'd' emitted from Source S. The wave from Both slit behave as it is emerging from S1 and S2.They travel in same medium and reaches at screen which is situated at a distance of D from slit source.
Let Point O is at equidistance from point S1 and S2 in same phase .Hence the point O will be Bright called as central bright. Now let R be any point at a distance 'x' from O . the path difference between the waves reaching R from S1 and S2 is (S1R - S2R) . Thus from figure above, Triangle S1MR and Triangle S2NR is right angled triangle.
Applying phythagoras theorem in S1MR ,
The distance between the center of two adjacent bright or dark bands is called as fringe width.
Fringe width of bright Bands: Let us consider two adjacent bright frindge at a distance xn and xn+1 from Central Bright. Then according to Youngs experiment,
xn = (nλD)/d----------(1)
xn+1 =((n+1)λD)/d) ---------------(2)
xn+1 - xn =((n+1) λD)/d) – (nλD)/d)
xn+1 - xn =(n+1-n) λD)/d
xn+1 - xn = (λD)/d
Fringe width of Dark Bands: Let us consider two adjacent Dark frindge at a distance xm and xm+1 from Central Bright. Then according to Youngs experiment,
xm = ((2m-1) λD)/2d----------(1)
xm+1 =(2(m+1-1) λD)/2d)-----------(2)
xm+1 - xm = (2(m+1)-1-2m+1) λD/2d)
xm+1 - xm = (λD)/d
│<<<Interference of light││ Fringe width>>>│
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